Optimal. Leaf size=214 \[ -\frac {2 b^3 (d+e x)^{3/2} (-4 a B e-A b e+5 b B d)}{3 e^6}+\frac {4 b^2 \sqrt {d+e x} (b d-a e) (-3 a B e-2 A b e+5 b B d)}{e^6}+\frac {4 b (b d-a e)^2 (-2 a B e-3 A b e+5 b B d)}{e^6 \sqrt {d+e x}}-\frac {2 (b d-a e)^3 (-a B e-4 A b e+5 b B d)}{3 e^6 (d+e x)^{3/2}}+\frac {2 (b d-a e)^4 (B d-A e)}{5 e^6 (d+e x)^{5/2}}+\frac {2 b^4 B (d+e x)^{5/2}}{5 e^6} \]
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Rubi [A] time = 0.09, antiderivative size = 214, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 33, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.061, Rules used = {27, 77} \[ -\frac {2 b^3 (d+e x)^{3/2} (-4 a B e-A b e+5 b B d)}{3 e^6}+\frac {4 b^2 \sqrt {d+e x} (b d-a e) (-3 a B e-2 A b e+5 b B d)}{e^6}+\frac {4 b (b d-a e)^2 (-2 a B e-3 A b e+5 b B d)}{e^6 \sqrt {d+e x}}-\frac {2 (b d-a e)^3 (-a B e-4 A b e+5 b B d)}{3 e^6 (d+e x)^{3/2}}+\frac {2 (b d-a e)^4 (B d-A e)}{5 e^6 (d+e x)^{5/2}}+\frac {2 b^4 B (d+e x)^{5/2}}{5 e^6} \]
Antiderivative was successfully verified.
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Rule 27
Rule 77
Rubi steps
\begin {align*} \int \frac {(A+B x) \left (a^2+2 a b x+b^2 x^2\right )^2}{(d+e x)^{7/2}} \, dx &=\int \frac {(a+b x)^4 (A+B x)}{(d+e x)^{7/2}} \, dx\\ &=\int \left (\frac {(-b d+a e)^4 (-B d+A e)}{e^5 (d+e x)^{7/2}}+\frac {(-b d+a e)^3 (-5 b B d+4 A b e+a B e)}{e^5 (d+e x)^{5/2}}+\frac {2 b (b d-a e)^2 (-5 b B d+3 A b e+2 a B e)}{e^5 (d+e x)^{3/2}}-\frac {2 b^2 (b d-a e) (-5 b B d+2 A b e+3 a B e)}{e^5 \sqrt {d+e x}}+\frac {b^3 (-5 b B d+A b e+4 a B e) \sqrt {d+e x}}{e^5}+\frac {b^4 B (d+e x)^{3/2}}{e^5}\right ) \, dx\\ &=\frac {2 (b d-a e)^4 (B d-A e)}{5 e^6 (d+e x)^{5/2}}-\frac {2 (b d-a e)^3 (5 b B d-4 A b e-a B e)}{3 e^6 (d+e x)^{3/2}}+\frac {4 b (b d-a e)^2 (5 b B d-3 A b e-2 a B e)}{e^6 \sqrt {d+e x}}+\frac {4 b^2 (b d-a e) (5 b B d-2 A b e-3 a B e) \sqrt {d+e x}}{e^6}-\frac {2 b^3 (5 b B d-A b e-4 a B e) (d+e x)^{3/2}}{3 e^6}+\frac {2 b^4 B (d+e x)^{5/2}}{5 e^6}\\ \end {align*}
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Mathematica [A] time = 0.11, size = 183, normalized size = 0.86 \[ \frac {2 \left (-5 b^3 (d+e x)^4 (-4 a B e-A b e+5 b B d)+30 b^2 (d+e x)^3 (b d-a e) (-3 a B e-2 A b e+5 b B d)+30 b (d+e x)^2 (b d-a e)^2 (-2 a B e-3 A b e+5 b B d)-5 (d+e x) (b d-a e)^3 (-a B e-4 A b e+5 b B d)+3 (b d-a e)^4 (B d-A e)+3 b^4 B (d+e x)^5\right )}{15 e^6 (d+e x)^{5/2}} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.93, size = 441, normalized size = 2.06 \[ \frac {2 \, {\left (3 \, B b^{4} e^{5} x^{5} + 256 \, B b^{4} d^{5} - 3 \, A a^{4} e^{5} - 128 \, {\left (4 \, B a b^{3} + A b^{4}\right )} d^{4} e + 96 \, {\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{3} e^{2} - 16 \, {\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d^{2} e^{3} - 2 \, {\left (B a^{4} + 4 \, A a^{3} b\right )} d e^{4} - 5 \, {\left (2 \, B b^{4} d e^{4} - {\left (4 \, B a b^{3} + A b^{4}\right )} e^{5}\right )} x^{4} + 10 \, {\left (8 \, B b^{4} d^{2} e^{3} - 4 \, {\left (4 \, B a b^{3} + A b^{4}\right )} d e^{4} + 3 \, {\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} e^{5}\right )} x^{3} + 30 \, {\left (16 \, B b^{4} d^{3} e^{2} - 8 \, {\left (4 \, B a b^{3} + A b^{4}\right )} d^{2} e^{3} + 6 \, {\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d e^{4} - {\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} e^{5}\right )} x^{2} + 5 \, {\left (128 \, B b^{4} d^{4} e - 64 \, {\left (4 \, B a b^{3} + A b^{4}\right )} d^{3} e^{2} + 48 \, {\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{2} e^{3} - 8 \, {\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d e^{4} - {\left (B a^{4} + 4 \, A a^{3} b\right )} e^{5}\right )} x\right )} \sqrt {e x + d}}{15 \, {\left (e^{9} x^{3} + 3 \, d e^{8} x^{2} + 3 \, d^{2} e^{7} x + d^{3} e^{6}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.25, size = 567, normalized size = 2.65 \[ \frac {2}{15} \, {\left (3 \, {\left (x e + d\right )}^{\frac {5}{2}} B b^{4} e^{24} - 25 \, {\left (x e + d\right )}^{\frac {3}{2}} B b^{4} d e^{24} + 150 \, \sqrt {x e + d} B b^{4} d^{2} e^{24} + 20 \, {\left (x e + d\right )}^{\frac {3}{2}} B a b^{3} e^{25} + 5 \, {\left (x e + d\right )}^{\frac {3}{2}} A b^{4} e^{25} - 240 \, \sqrt {x e + d} B a b^{3} d e^{25} - 60 \, \sqrt {x e + d} A b^{4} d e^{25} + 90 \, \sqrt {x e + d} B a^{2} b^{2} e^{26} + 60 \, \sqrt {x e + d} A a b^{3} e^{26}\right )} e^{\left (-30\right )} + \frac {2 \, {\left (150 \, {\left (x e + d\right )}^{2} B b^{4} d^{3} - 25 \, {\left (x e + d\right )} B b^{4} d^{4} + 3 \, B b^{4} d^{5} - 360 \, {\left (x e + d\right )}^{2} B a b^{3} d^{2} e - 90 \, {\left (x e + d\right )}^{2} A b^{4} d^{2} e + 80 \, {\left (x e + d\right )} B a b^{3} d^{3} e + 20 \, {\left (x e + d\right )} A b^{4} d^{3} e - 12 \, B a b^{3} d^{4} e - 3 \, A b^{4} d^{4} e + 270 \, {\left (x e + d\right )}^{2} B a^{2} b^{2} d e^{2} + 180 \, {\left (x e + d\right )}^{2} A a b^{3} d e^{2} - 90 \, {\left (x e + d\right )} B a^{2} b^{2} d^{2} e^{2} - 60 \, {\left (x e + d\right )} A a b^{3} d^{2} e^{2} + 18 \, B a^{2} b^{2} d^{3} e^{2} + 12 \, A a b^{3} d^{3} e^{2} - 60 \, {\left (x e + d\right )}^{2} B a^{3} b e^{3} - 90 \, {\left (x e + d\right )}^{2} A a^{2} b^{2} e^{3} + 40 \, {\left (x e + d\right )} B a^{3} b d e^{3} + 60 \, {\left (x e + d\right )} A a^{2} b^{2} d e^{3} - 12 \, B a^{3} b d^{2} e^{3} - 18 \, A a^{2} b^{2} d^{2} e^{3} - 5 \, {\left (x e + d\right )} B a^{4} e^{4} - 20 \, {\left (x e + d\right )} A a^{3} b e^{4} + 3 \, B a^{4} d e^{4} + 12 \, A a^{3} b d e^{4} - 3 \, A a^{4} e^{5}\right )} e^{\left (-6\right )}}{15 \, {\left (x e + d\right )}^{\frac {5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.05, size = 469, normalized size = 2.19 \[ -\frac {2 \left (-3 b^{4} B \,x^{5} e^{5}-5 A \,b^{4} e^{5} x^{4}-20 B a \,b^{3} e^{5} x^{4}+10 B \,b^{4} d \,e^{4} x^{4}-60 A a \,b^{3} e^{5} x^{3}+40 A \,b^{4} d \,e^{4} x^{3}-90 B \,a^{2} b^{2} e^{5} x^{3}+160 B a \,b^{3} d \,e^{4} x^{3}-80 B \,b^{4} d^{2} e^{3} x^{3}+90 A \,a^{2} b^{2} e^{5} x^{2}-360 A a \,b^{3} d \,e^{4} x^{2}+240 A \,b^{4} d^{2} e^{3} x^{2}+60 B \,a^{3} b \,e^{5} x^{2}-540 B \,a^{2} b^{2} d \,e^{4} x^{2}+960 B a \,b^{3} d^{2} e^{3} x^{2}-480 B \,b^{4} d^{3} e^{2} x^{2}+20 A \,a^{3} b \,e^{5} x +120 A \,a^{2} b^{2} d \,e^{4} x -480 A a \,b^{3} d^{2} e^{3} x +320 A \,b^{4} d^{3} e^{2} x +5 B \,a^{4} e^{5} x +80 B \,a^{3} b d \,e^{4} x -720 B \,a^{2} b^{2} d^{2} e^{3} x +1280 B a \,b^{3} d^{3} e^{2} x -640 B \,b^{4} d^{4} e x +3 A \,a^{4} e^{5}+8 A \,a^{3} b d \,e^{4}+48 A \,a^{2} b^{2} d^{2} e^{3}-192 A a \,b^{3} d^{3} e^{2}+128 A \,b^{4} d^{4} e +2 B \,a^{4} d \,e^{4}+32 B \,d^{2} a^{3} b \,e^{3}-288 B \,d^{3} a^{2} b^{2} e^{2}+512 B a \,b^{3} d^{4} e -256 B \,b^{4} d^{5}\right )}{15 \left (e x +d \right )^{\frac {5}{2}} e^{6}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.65, size = 416, normalized size = 1.94 \[ \frac {2 \, {\left (\frac {3 \, {\left (e x + d\right )}^{\frac {5}{2}} B b^{4} - 5 \, {\left (5 \, B b^{4} d - {\left (4 \, B a b^{3} + A b^{4}\right )} e\right )} {\left (e x + d\right )}^{\frac {3}{2}} + 30 \, {\left (5 \, B b^{4} d^{2} - 2 \, {\left (4 \, B a b^{3} + A b^{4}\right )} d e + {\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} e^{2}\right )} \sqrt {e x + d}}{e^{5}} + \frac {3 \, B b^{4} d^{5} - 3 \, A a^{4} e^{5} - 3 \, {\left (4 \, B a b^{3} + A b^{4}\right )} d^{4} e + 6 \, {\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{3} e^{2} - 6 \, {\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d^{2} e^{3} + 3 \, {\left (B a^{4} + 4 \, A a^{3} b\right )} d e^{4} + 30 \, {\left (5 \, B b^{4} d^{3} - 3 \, {\left (4 \, B a b^{3} + A b^{4}\right )} d^{2} e + 3 \, {\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d e^{2} - {\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} e^{3}\right )} {\left (e x + d\right )}^{2} - 5 \, {\left (5 \, B b^{4} d^{4} - 4 \, {\left (4 \, B a b^{3} + A b^{4}\right )} d^{3} e + 6 \, {\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{2} e^{2} - 4 \, {\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d e^{3} + {\left (B a^{4} + 4 \, A a^{3} b\right )} e^{4}\right )} {\left (e x + d\right )}}{{\left (e x + d\right )}^{\frac {5}{2}} e^{5}}\right )}}{15 \, e} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.00, size = 413, normalized size = 1.93 \[ \frac {{\left (d+e\,x\right )}^{3/2}\,\left (2\,A\,b^4\,e-10\,B\,b^4\,d+8\,B\,a\,b^3\,e\right )}{3\,e^6}-\frac {\left (d+e\,x\right )\,\left (\frac {2\,B\,a^4\,e^4}{3}-\frac {16\,B\,a^3\,b\,d\,e^3}{3}+\frac {8\,A\,a^3\,b\,e^4}{3}+12\,B\,a^2\,b^2\,d^2\,e^2-8\,A\,a^2\,b^2\,d\,e^3-\frac {32\,B\,a\,b^3\,d^3\,e}{3}+8\,A\,a\,b^3\,d^2\,e^2+\frac {10\,B\,b^4\,d^4}{3}-\frac {8\,A\,b^4\,d^3\,e}{3}\right )+{\left (d+e\,x\right )}^2\,\left (8\,B\,a^3\,b\,e^3-36\,B\,a^2\,b^2\,d\,e^2+12\,A\,a^2\,b^2\,e^3+48\,B\,a\,b^3\,d^2\,e-24\,A\,a\,b^3\,d\,e^2-20\,B\,b^4\,d^3+12\,A\,b^4\,d^2\,e\right )+\frac {2\,A\,a^4\,e^5}{5}-\frac {2\,B\,b^4\,d^5}{5}+\frac {2\,A\,b^4\,d^4\,e}{5}-\frac {2\,B\,a^4\,d\,e^4}{5}-\frac {8\,A\,a\,b^3\,d^3\,e^2}{5}+\frac {8\,B\,a^3\,b\,d^2\,e^3}{5}+\frac {12\,A\,a^2\,b^2\,d^2\,e^3}{5}-\frac {12\,B\,a^2\,b^2\,d^3\,e^2}{5}-\frac {8\,A\,a^3\,b\,d\,e^4}{5}+\frac {8\,B\,a\,b^3\,d^4\,e}{5}}{e^6\,{\left (d+e\,x\right )}^{5/2}}+\frac {2\,B\,b^4\,{\left (d+e\,x\right )}^{5/2}}{5\,e^6}+\frac {4\,b^2\,\left (a\,e-b\,d\right )\,\sqrt {d+e\,x}\,\left (2\,A\,b\,e+3\,B\,a\,e-5\,B\,b\,d\right )}{e^6} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 5.28, size = 2440, normalized size = 11.40 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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